不定长字符串,截取后面的第二个到第三个字符HI。
text = 'AB。。。CDEFGHIJ'.
len = strlen( text ) - 3.
SHIFT text by len LEFT.
result_HI = text+0(2).
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SHIFT dobj
[{BY num PLACES} | {UP TO sub_string}]
[LEFT|RIGHT] [CIRCULAR]
SHIFT dobj
{LEFT DELETING LEADING} | {RIGHT DELETING TRAILING} pattern.
[IN {BYTE|CHARACTER} MODE].
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